Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.3 Adding and Subtracting Unlike Fractions - 3.3 Exercises - Page 219: 9

Answer

$\frac{39}{40}$

Work Step by Step

The LCD of the original denominators, 5 and 8, is 40. Therefore, we can rewrite both fractions with a denominator of 40. $\frac{3}{5}+\frac{3}{8}=\frac{3\times8}{5\times8}+\frac{3\times5}{8\times5}=\frac{24}{40}+\frac{15}{40}=\frac{24+15}{40}=\frac{39}{40}$
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