Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.3 Adding and Subtracting Unlike Fractions - 3.3 Exercises - Page 219: 7

Answer

$\frac{3}{4}$

Work Step by Step

The LCD of the original denominators, 10 and 20, is 20. Therefore, we can rewrite both fractions with a denominator of 20. $\frac{9}{20}+\frac{3}{10}=\frac{9}{20}+\frac{3\times2}{10\times2}=\frac{9}{20}+\frac{6}{20}=\frac{9+6}{20}=\frac{15}{20}=\frac{3}{4}$
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