Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 2 - Multiplying and Dividing Fractions - 2.4 Writing a Fraction in Lowest Terms - 2.4 Exercises - Page 137: 37

Answer

$\frac{1}{2}$

Work Step by Step

$\frac{90}{180}=\frac{2\times3\times3\times5}{2\times2\times3\times3\times5}=\frac{2\times3\times3\times5}{2\times3\times3\times5}\times\frac{1}{2}=1\times\frac{1}{2}=\frac{1}{2}$
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