Chapter 8 - Right Triangles and Trigonometry - 8-3 Trigonometry - Practice and Problem-Solving Exercises - Page 510: 13

$\ Sin=\dfrac{\sqrt 3}{2}$ $\ Cos=\dfrac{1}{2}$ $\ Tan=\sqrt 3$

The Trigonometric ratios can be written as follows: $\ Sin=\dfrac{Opposite}{hypotenuse}=\dfrac{ 2\sqrt 3}{4} =\dfrac{\sqrt 3}{2}$ $\ Cos=\dfrac{Aadjacent}{hypotenuse}=\dfrac{2}{4}=\dfrac{1}{2}$ $\ Tan=\dfrac{Opposite}{Adjacent}=\dfrac{2\sqrt 3}{2}=\sqrt 3$