Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-3 Trigonometry - Practice and Problem-Solving Exercises - Page 510: 12

Answer

Sin=$\frac{4\sqrt 2}{9}$ Cos=$\frac{7}{9}$ Tan=$\frac{4\sqrt 2}{7}$

Work Step by Step

Sin=$\frac{opposite}{hypotenuse}$=$\frac{4\sqrt 2}{9}$ Cos=$\frac{adjacent}{hypotenuse}$=$\frac{7}{9}$ Tan=$\frac{opposite}{adjacent}$=$\frac{4\sqrt 2}{7}$
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