Answer
None
Work Step by Step
Our aim is to apply the distance formula to compute the type of triangle that is given in the picture.
We are given that the parallelogram with are $P(-1,2)$, $O(0, 0)$, and $S(4,0)$ and $T(3,2)$.
The distance formula is given by the following formula:
$d = \sqrt {(x_2 - x_1)^2 + (y_2 - y_1)^2}$
We will compute the lengths of two adjacent sides of the parallelogram.
$PO= \sqrt {(0-(-1))^2 + (0-2)^2}=\sqrt 5$ and $OS= \sqrt {(4-0)^2 + (0-0)^2}=4$
We can see that $PO \ne OS$, this implies that the parallelogram is neither a square and not a rhombus.
