Answer
15120
Work Step by Step
Order does matter, so we must use a permutation.
We know that:
$_nP_r = \frac{n!}{(n-r)!}$
$_9P_5 = \frac{9!}{(9-5)!}$
$\frac{9!}{4!}$
We also know that:
$x! = x(x-1)(x-2)...(1)$
Thus, we have:
15120
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