Answer
56
Work Step by Step
We know that:
$_nC_r =\frac{_nP_r}{r!} = \frac{n!}{(n-r)!r!}$
$_8C_5 = \frac{8!}{(8-5)!5!}$
$\frac{ 8!}{3!5!}$
We also know that:
$x! = x(x-1)(x-2)...(1)$
Thus, we have:
56
Geometry: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281159
ISBN 13:
978-0-13328-115-6
Chapter 13 - Probability - Mid-Chapter Quiz - Page 843: 13
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
