Answer
$(\frac{a-c}{b}, a)$
Work Step by Step
$y=a$
$y=bx+c$
In this problem we want to equate the two expressions for y and solve for x, while treating a, b, and c as constants.
$a=bx+c$
$a-c=bx$
$x=\frac{a-c}{b}$
Since it is given in the problem that $y=a$, our answer is $(\frac{a-c}{b}, a)$.
