Chapter 10 - Section 10.5 - Equations of Lines - Exercises - Page 480: 37

$(5, -2)$

$2x + 3y = 4$ $3x - 4y= 23$ When we multiply the first equation by 4 and the second equation by 3, the system becomes $8x + 12y = 16$ $9x - 12y = 69$ Adding these equations yields $17x = 85$, so $x = 5$. Substituting $x = 5$ into the first equation, we get $10 + 3y = 4$, so $3y = -6$. Then $y = -2$. So the solution is $(5, -2)$.