Answer
$2 \sqrt {a^{2} + b^{2}}$
Work Step by Step
$d = \sqrt {(a - -a)^{2} + (b - -b)^{2}}$
$d = \sqrt {(2a)^{2} + (2b)^{2}}$
$d = \sqrt {4a^{2} + 4b^{2}}$
$d = \sqrt {4(a^{2} + b^{2})}$
$d = 2 \sqrt {a^{2} + b^{2}}$
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 10 - Section 10.1 - The Rectangular Coordinate System - Exercises - Page 449: 8c
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