Answer
$2 \sqrt {10}$
Work Step by Step
$d = \sqrt {(-2 - 0)^{2} + (6 - 0)^{2}}$
$d = \sqrt {(-2)^{2} + (6)^{2}}$
$d = \sqrt {4 + 36}$
$d = \sqrt {40}$
$d = \sqrt {4} \sqrt {10}$
$d = 2 \sqrt {10}$
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 10 - Section 10.1 - The Rectangular Coordinate System - Exercises - Page 449: 8b
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