Answer
$12\pi$
Work Step by Step
We first find the height of the circle:
$h = \sqrt{8^2 - 4^2} = \sqrt{48} = 4\sqrt{3}$
Since this height is double the radius, we find: $r = 2 \sqrt{3}$
Thus, we find area:
$ A = \pi(2\sqrt{3})^2 = 12\pi$
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 8 - Section 8.4 - Circumference and Area of a Circle - Exercises - Page 374: 47
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