Answer
$\approx$16.76 feet per second
Work Step by Step
Given The radius of the Ferris wheel’s circular path is 40 ft. If a “ride” of 12 revolutions is made in 3 minutes, at what rate in feet per second is the passenger in a cart moving during the ride
Given radius of the wheel = 40 ft
So one revolution = circumference of the wheel
= 2 * $\pi$ * 40
= 80$\pi$
The wheel rotate 12 times for a ride, So total circumference = 12 * 80$\pi$
= 960 $\pi$
As we know speed = $\frac{distance}{time}$ = $\frac{ 960 \pi}{ 3 min}$
= $\frac{960 \pi}{180 sec}$ ( as we know 1 min = 60 sec)
= 16.76 feet per sec
So the passenger in a cart moving during the ride at a rate of 16.76 feet per second.
