Chapter 5 - Section 5.2 - Similar Polygons - Exercises - Page 224: 37

The TV should have a diagonal of $50.3''$

Let $D_1 = 32''$ and let $L_1 = 7 ~ft$ Let $L_2 = 11~ft$ We can find $D_2$: $\frac{D_2}{L_2} = \frac{D_1}{L_1}$ $D_2 = (\frac{D_1}{L_1})~(L_2)$ $D_2 = (\frac{32''}{7~ft})~(11~ft)$ $D_2 = 50.3''$ The TV should have a diagonal of $50.3''$