Answer
BC$\approx$14.5
Work Step by Step
$\frac{AC}{EA}$=$\frac{BC}{DE}$
$\frac{20}{20-BC}$=$\frac{BC}{4}$
20BC-BC$^2$=80
BC$^2$-20BC+80=0
BC=$\frac{20+\sqrt {400-320}}{2}$
BC=10+.5$\sqrt {80}$
BC$\approx$14.5
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 5 - Section 5.2 - Similar Polygons - Exercises - Page 224: 23
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
