University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.6 - Cylinders and Quadric Surfaces - Exercises - Page 636: 36

Answer

Elliptical cylinder. See image: .

Work Step by Step

There is no z in the equation; thus we have a cylinder. In the xy-plane ($z=0$), the trace is an ellipse $\displaystyle \frac{x^{2}}{(1/4)^{2}}+\frac{y^{2}}{(1/2)^{2}}=1$ and similarly in all the planes parallel to $z=0$. The resulting surface is an elliptical cylinder, with the z-axis as its axis.
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