University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.6 - Cylinders and Quadric Surfaces - Exercises - Page 636: 34

Answer

Elliptical (circular) cone. See image: .

Work Step by Step

Dividing with 4, we rewrite the equation as: $\displaystyle \frac{x^{2}}{1^{2}}+\frac{y^{2}}{1^{2}}=\frac{z^{2}}{2^{2}}$ and comparing to Table 11.1, we recognize the form of Elliptical cone. The cross sections with planes $z=k$ are circles (at $z=\pm 2,$ the radius is 1). We know that circles are special cases of ellipses.
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