Answer
${\bf( 2i-j)}\times{\bf (i+2j)}=5{\bf k}$
.
Work Step by Step
${\bf( 2i-j)}\times{\bf (i+2j)}=\left|\begin{array}{lll}
{\bf i} & {\bf j} & {\bf k}\\
2 & -1 & 0\\
1 & 2 & 0
\end{array}\right|$
$=(0)-(0)+(4+1){\bf k}$
$=5{\bf k}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 11 - Section 11.4 - The Cross Product - Exercises - Page 622: 12
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