University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.3 - The Dot Product - Exercises - Page 617: 38

Answer

$3x-2y=4$

Work Step by Step

The result of exercise 32 tells us that ${\bf v}=\langle a,\ b \rangle$ is parallel to the lines $bx-ay=c$. Here, ${\bf v}=\langle 2,\ 3 \rangle$ and the lines are $3x-2y=c.$ Since $P(0,-2)$ is on the line, its coordinates satisfy the line equation $\left\{\begin{array}{l} 3(0)-2(-2)=c\\ c=4 \end{array}\right.$ So the line equation is: $\quad 3x-2y=4$ To graph the line, use the given point and $(2,1)$.
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