Answer
$2x-3y=-8$
Work Step by Step
The result of exercise 31 tells us that ${\bf v}=\langle a,\ b \rangle$ is perpendicular to lines $ax+by=c$.
Here, ${\bf v}=\langle 2,\ -3 \rangle$ and the lines are $2x-3y=c.$
Since $P(11,10)$ is on the line, its coordinates satisfy the line equation
$\left\{\begin{array}{l}
2(11)-3(10)=c\\
c=-8
\end{array}\right.$
So the line equation is: $\quad 2x-3y=-8$.
To graph the line, use the given point and $(-4,0)$.
