Answer
$7 ; \lt \dfrac{2}{7},\dfrac{-3}{7},\dfrac{6}{7}\gt$
Work Step by Step
Here, $|v|=\sqrt{(2)^2+(-3)^2+(6)^2}=\sqrt {49}=7$
The unit vector $\hat{\textbf{u}}$ can be calculated as: $\hat{\textbf{u}}=\dfrac{v}{|v|}$
Now, $\hat{\textbf{u}}=\dfrac{\lt 2,-3,6 \gt}{7}= \lt \dfrac{2}{7},\dfrac{-3}{7},\dfrac{6}{7}\gt$
Thus, our final answers are: $7 ; \lt \dfrac{2}{7},\dfrac{-3}{7},\dfrac{6}{7}\gt$
