Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.4 - Exponential Change and Separable Differential Equations - Exercises 7.4 - Page 402: 38

Answer

$\approx 600$ days

Work Step by Step

Consider the exponential growth equation as follows: $A=A_0e^{kt}$ As we are given that $A=\dfrac{1}{2} A_0$ Now, we have $(\dfrac{1}{2}) A_0=A_0e^{(139)k} \implies k =\dfrac{\ln 0.5}{(139)}$ or, $k\approx -0.00499$ years Now, we have $A=A_0e^{kt} \implies (0.05)A_0=A_0 e^{-0.00499t}$ or, $t=\dfrac{\ln (0.05)}{-(0.00499)}$ Thus, $t\approx 600$ days
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