Answer
$\approx 585.35$kg
Work Step by Step
Consider the equation $A=A_0e^{k t}$
As we are given that $A_0=1000$ and $A= 800$
Then, we have $k=\dfrac{\ln (0.8)}{10}$
or, $A=(1000) e^{\dfrac{\ln (0.8)t}{10}}$
After another $t = 14 hours$ , we have $t=14+10 =24$
Thus, $A= (1000) e^{[\frac{\ln (0.8)(24)}{10}]} \implies A \approx 585.35$kg
