Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 288: 67

Answer

$f(x)=2x-2$

Work Step by Step

The function $f(x)$ is the derivative of $\int_1^{x} f(t) dt=x^2-2x+1$ by the fundamental Theorem of calculus. This implies that $\int_1^{x} f(t) dt=x^2-2x+1$ $\implies f(x)=2x-2$
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