Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 288: 65

Answer

(a) $70^{\circ} F, 76^{\circ} F, 85^{\circ} F$ and (b) $75^{\circ} F$

Work Step by Step

(a) Consider: $T(t)=85-3\sqrt {25-t}$ Now, $T(0)=85-15=70^{\circ} F; \\ T(16)=85-9=76^{\circ} F; \\ T(25)=85^{\circ} F$ b) Let us consider the integral $T=\dfrac{1}{25}\int_{0}^{25} 85 - 3\sqrt {25-t} dt=\dfrac{1}{25} (85(25)+0-0-(2)(125)]=75^{\circ} F$ or, $T=\dfrac{1}{25} (85(25)+0-0-(2)(125)]=75^{\circ} F$
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