Answer
$1$
Work Step by Step
Given:$\int_{0}^{\frac{\pi}{4}}$$\sec^2x$$dx$
$=>$$\tan x$$]$$_{0}^{\frac{\pi}{4}}$
Now, we apply the limits:
$=>$ $\tan\frac{\pi}{4}$$-$$\tan0$
$=>$$1$$-$$0$$= $$1$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 278: 92
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