Answer
$0$
Work Step by Step
Given: $\int_{-\pi}^{\pi}$$\cos x dx$
$=>$$[$$\sin x$$]$$_{-\pi}^{\pi}$
Now, we apply the limits
$=>$$\sin\pi$$-$$\sin(-\pi)$
$=>$$\sin\pi$$+$$\sin\pi$
$=>$$2\sin\pi$
$=>$$2(0)$$=$$0$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.3 - The Definite Integral - Exercises 5.3 - Page 278: 91
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