Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.8 - Related Rates - Exercises 3.8 - Page 161: 7

Answer

$\dfrac{dy}{dt} = \dfrac{-3}{2}$

Work Step by Step

Given that $\dfrac{dx}{dt} = -2$ and $x^2+y^2=25$ Thus,on differentiating with respect to time or, $2x\dfrac{dx}{dt} + 2y\dfrac{dy}{dt} =0 $ Now, when $x=3, y=-4$; then $ -8\dfrac{dy}{dt} - 2\times (-2)\times3=0$ $ \implies \dfrac{dy}{dt} = \dfrac {-3}{2}$ Thus, the answer is: $\dfrac{dy}{dt} = \dfrac{-3}{2}$
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