Answer
$\dfrac{dx}{dt} = 55$
Work Step by Step
Given: $\dfrac{dy}{dt} = 5$ and $x=y^3-y$
Thus, on differentiating $x$ with respect to time, we get
and $\dfrac{dx}{dt} = \dfrac{3y^2dy}{dt}-\dfrac{dy}{dt}$
Now, when $y=2$; then$ \dfrac{dx}{dt} = 3\times (4)\times5-5$
Thus, the answer is: $\dfrac{dx}{dt} = 55$