Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.5 - Derivatives of Trigonometric Functions - Exercises 3.5 - Page 142: 48

Answer

$\sqrt 2$

Work Step by Step

$\lim_{x\to-\pi/6}\sqrt {1+cos(\pi csc(x))}=\sqrt {1+cos(\pi csc(-\pi/6))}=\sqrt {1+cos(\pi(-2))}=\sqrt {1+cos(2\pi)}=\sqrt 2$
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