Answer
a. $v(t)=9.8t$
b. $9.8m/s^2$
Work Step by Step
a. Given $v(t)=9.8(sin\theta) t$ m/sec, letting $\theta=90^{\circ}$, we have $sin\theta=1$ and the equation for the ball’s velocity during free fall is $v(t)=9.8t$
b. Based on the velocity equation above, we can find the acceleration as $a=v'=9.8m/s^2$
