Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 181: 114

Answer

$5~rad/sec$.

Work Step by Step

Step 1. We are given $v=6ft/sec, r=1.2ft$ Step 2. Using the equation $s=r\theta$, take $r$ as a constant. Here, we have $v=\frac{ds}{dt}=r\frac{d\theta}{dt}$ and $\frac{d\theta}{dt}=\frac{v}{r}=\frac{6}{1.2}=5rad/sec$.
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