Answer
$\frac{9}{2}$
Work Step by Step
$\int^{2}_{-1} \int^{y+2}_{y^2}dxdy$
=$[\frac{}{}+2y-\frac{y^3}{3}]_{-1}^2$
=(2+4-8/3)-(1/2-2+1/3)
=5-1/2=9/2
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 15: Multiple Integrals - Section 15.3 - Area by Double Integration - Exercises 15.3 - Page 887: 16
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