Answer
=$2\ln2-1$
Work Step by Step
$\int^1_0\int^1_0\frac{y}{1+x}dxdy$
=$\int^1_0[\ln|1+xy|]^1_0dy$
=$\int^1_0\ln|1+y|dy$
=$[y\ln|1+y|-y+\ln|1+y|]^1_0$
=$2\ln2-1$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 15: Multiple Integrals - Section 15.1 - Double and Iterated Integrals over Rectangles - Exercises 15.1 - Page 874: 7
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