Answer
=$\frac{3}{2}$
Work Step by Step
$\int^1_0\int^2_1xye^xdydx$
=$\int^1_0[\frac{1}{2}xy^2e^x]^2_1dx$
=$\int^1_0\frac{3}{2}xe^xdx$
=$[\frac{3}{2}xe^x-\frac{3}{2}e^x]^1_0$
=$\frac{3}{2}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 15: Multiple Integrals - Section 15.1 - Double and Iterated Integrals over Rectangles - Exercises 15.1 - Page 874: 10
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
