Answer
$\dfrac{\sqrt {42}}{3}$
Work Step by Step
The distance formula for two vectors can be calculated as:
$d=\dfrac{|p \times q|}{|q|}$
Thus, we have $p \times q=\lt -2,6,-4\gt $
and $|p \times q|=\sqrt{(-2)^2+(6)^2+(-4)^2}=\sqrt{4+36+16}=2 \sqrt {14}$
Thus, $d=\dfrac{2 \sqrt {14}}{2 \sqrt {3}}=\dfrac{\sqrt {42}}{3}$
