Answer
$x+3y+4z=34$
Work Step by Step
The standard equation of plane passing through the point $(a,b,c)$ is given as $p(x-a)+q(y-b)+r(z-c)=0$
The equation of normal to the plane;$n=\lt 1,3,4 \gt$
For point $(2,4,5)$, we get
$1(x-2)+3(y-4)+4(z-5)=0$
or, $x-2+3y-12+4z-20=0$
Thus, $x+3y+4z=34$
