Answer
Magnitude of x-component,then cos 45=|x|\|F|.
|x|=|F|cos 45=12(2^1\2\2)=62^1\2)Ib.
Fx=-6^1\2i (negative sign shown)
Magnitude of Y- component then sin 45 = |y|\|F|.
|Y| = |F| sin 45 = 12(2^1\2) = 6(2^1\2\2)Ib.
Fy = -6(2^1\2j) (negative sign shown in diagram).
Work Step by Step
Magnitude of x-component,then cos 45=|x|\|F|.
|x|=|F|cos 45=12(2^1\2\2)=62^1\2)Ib.
Fx=-6^1\2i (negative sign shown)
Magnitude of Y- component then sin 45 = |y|\|F|.
|Y| = |F| sin 45 = 12(2^1\2) = 6(2^1\2\2)Ib.
Fy = -6(2^1\2j) (negative sign shown in diagram).
