Answer
${\bf i}\times{\bf (i+j)}={\bf k}$
Work Step by Step
${\bf i}\times{\bf (i+j)}=\left|\begin{array}{lll}
{\bf i} & {\bf j} & {\bf k}\\
1 & 0 & 0\\
1 & 1 & 0
\end{array}\right|$
$=(0-0){\bf i}-(0-0){\bf j}+(1-0){\bf k}={\bf k}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 12: Vectors and the Geometry of Space - Practice Exercises - Page 734: 21
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