Answer
$\sqrt 2 ; \lt \dfrac{-1}{\sqrt 2},\dfrac{-1}{\sqrt 2} \gt$
Work Step by Step
As we know that the unit vector $\hat{\textbf{u}}$ is defined as: $\hat{\textbf{u}}=\dfrac{v}{|v|}$
Now, we have: $|v|=\sqrt{(-1)^2+(-1)^2}=\sqrt {2}$
Thus, $\hat{\textbf{u}}=\dfrac{v}{|v|}=\dfrac{\lt -1,-1 \gt}{\sqrt 2}= \lt \dfrac{-1}{\sqrt 2},\dfrac{-1}{\sqrt 2} \gt$
