Answer
Solution set = $\{-3,3\}$
Work Step by Step
Use properties from the table 'Absolute Values and Intervals".
Here: property 5:
$\quad |x|=a \Leftrightarrow x=\pm a,\ \quad $
which holds for any positive number a.
Thus:
$y=\pm 3$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Appendices - Section A.1 - Real Numbers and the Real Line - Exercises A.1 - Page AP-6: 7
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