Answer
$x\in(-\infty,-0)\cup(2,\infty)$
Work Step by Step
Use properties from the table 'Absolute Values and Intervals".
Applying Property 7:
$|x|\gt a\quad\Leftrightarrow\quad x\gt a\ \ $or$\ \ x\lt-a, \quad $ for a = positive number
We have
$\begin{array}{ll}
1-x\gt 1 & /-1\\
-x\gt0 & /\times(-1)\\
x\lt 0 &
\end{array}$ $\ \ $
or
$\ \ $ $\begin{array}{ll}
1-x\lt -1 & /-1\\
-x\lt -2 & /\times(-1)\\
x\gt2 & \\
&
\end{array}$
In interval form, we can write this result as
$x\in(-\infty,-0)\cup(2,\infty)$
