Answer
$(1,1), (\frac{3}{4},\frac{1}{2}), (\frac{1}{2}, 1-\frac{\sqrt 2}{2}), (\frac{1}{4},1-\frac{\sqrt 3}{2}),$ and $(0,0)$ are consecutive points on the curve. The arrow points from $(1,1)$ to $(0,0)$.
![](https://gradesaver.s3.amazonaws.com/uploads/solution/f1951a4a-7605-4427-b5a2-28aa940424f7/result_image/1487887223.png?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20250215%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20250215T144146Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=c36e92ebc9a81fe0b54eb2b71c2a0ff60470d019d1f03dd6712f98164761d6ab)
Work Step by Step
Since $0 \leq t \leq \frac{\pi}{2},$ plot the points where $t=0,$ $t=\frac{\pi}{6},$ $t=\frac{\pi}{4},$ $t=\frac{\pi}{3},$ and $t=\frac{\pi}{2}$. You can find the $x$ and $y$ coordinates of each point by plugging the value of $t$ into the given formulas for $x$ and $y$. For instance, when $t=0,$
$$x = (\cos0)^2=1$$$$y = 1 - \sin0 = 1$$ Therefore, $t=0$ corresponds to the point $(1,1)$.
The same calculation gives:
$(\frac{3}{4},\frac{1}{2})$ for $t=\frac{\pi}{6}$
$(\frac{1}{2}, 1-\frac{\sqrt 2}{2})$ for $t=\frac{\pi}{4}$
$(\frac{1}{4},1-\frac{\sqrt 3}{2})$ for $t=\frac{\pi}{3}$
$(0,0)$ for $t=\frac{\pi}{2}$
Plot these five points and connect them with a curve (in order of increasing $t$), as shown.
As $t$ increases from $0$ to $\frac{\pi}{2}$, the curve is traced from $(1,1)$ to $(0,0)$, so an arrow should be drawn on the curve in that direction, as shown.