Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 1 - Section 1.3 - Linear Functions and Models - Exercises - Page 90: 6

Answer

m=$-\displaystyle \frac{2}{3}$, fill y = $-3$

Work Step by Step

From the two points ($0.,-1)$ and $(6,-5)$ $m=\displaystyle \frac{\Delta y}{\Delta x}=\frac{change\ in\ y}{change\ in\ x}\\\\=\dfrac{-5-(-1)}{6-0}=\dfrac{-4}{6}=-\dfrac{2}{3}$, which we read also as: "for a change of x of $+3$, y changes by $-2$" (rise and run) So, when x changes from $0$ to $3$, (by $+3$) y will change from $-1 $ to $-3$ (by $-2$). Missing point: ($3,-3$)
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