Answer
please see image:
Work Step by Step
First objective: write the equation in the form $y=mx+b$;
$2x=3y$
$3y=2x\qquad/\div 3$
$y=\displaystyle \frac{2}{3}x$
from where we read:
slope =$\displaystyle \frac{2}{3}$, y-intercept = 0.
Now,
From here, we read: slope =0, y-intercept=$\displaystyle \frac{4}{3}$
1. Plot the point $(0,0)$.
2. Using $m=\displaystyle \frac{\Delta y}{\Delta x} =\displaystyle \frac{Rise}{Run}=\frac{2}{3}$,
for a change in x of 3,
y changes by +2,
which leads us to the point $(0+3,0+2)=(3,2)$
We now have two points...
Draw a straight line through $(0,0)$ and $(3,2)$.
