Answer
$h(x^2+1)=\frac{1}{x^2+5}$
Work Step by Step
$h(r)=\frac{1}{r+4}$
Substitute $r$ with $x^2+1$
$h(x^2+1)=\frac{1}{x^2+1+4}=\frac{1}{x^2+5}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 1 - Section 1.1 - Functions from the Numerical, Algebraic, and Graphical Viewpoints - Exercises - Page 52: 18e
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