Answer
$(s+h)^{2}+\displaystyle \frac{1}{s+h}-(s^{2}+\frac{1}{s})$
Work Step by Step
Use the result of (f)
$g(s+h)=(s+h)^{2}+\displaystyle \frac{1}{s+h}$
$g(s+h)-g(s)=(s+h)^{2}+\displaystyle \frac{1}{s+h}-(s^{2}+\frac{1}{s})$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 1 - Section 1.1 - Functions from the Numerical, Algebraic, and Graphical Viewpoints - Exercises - Page 52: 17f
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