Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 1 - Review - Review Exercises - Page 107: 22

Answer

The equation of that line is: $y = \frac{1}{2}x - 1$

Work Step by Step

1. Find the point where these 2 functions intersect: - At the x-intercept, the value for "y" is equal to 0, so the function pass through the "x axis". - Find the value for "x" when y = 0 in the "3x + y = 6" equation: $3x + (0) = 6$ $3x = 6$ $\frac{3x}{3} = \frac{6}{3}$ $x = 2$ - Therefore, the specified line pass through (2, 0). 2. The patter equation for a line is: "y = mx + b", and we know that the slope (m) is equal to $\frac{1}{2}$. $y = \frac{1}{2} x + b$ 3. Substitute the x and y values (2, 0) in the equation and solve for b. $0 = \frac{1}{2}(2) + b$ $0 = 1 +b$ $0 - 1 = 1 + b - 1$ $-1 = b$ 4. Write the equation of the specified line: $y = \frac{1}{2}x - 1$
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