Answer
$\frac{9}{4}\sqrt[3] (1-x)^{7}$
Work Step by Step
$\frac{9}{4(1-x)^{-\frac{7}{3}}}=\frac{9}{4}\times\frac{1}{(1-x)^{-\frac{7}{3}}}=\frac{9}{4}\times\frac{1}{\frac{1}{(1-x)^{\frac{7}{3}}}}=\frac{9}{4}(1-x)^{\frac{7}{3}}=\frac{9}{4}\sqrt[3] (1-x)^{7}$